F(x)=5x^2+4x+11

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Solution for F(x)=5x^2+4x+11 equation: 



(F)=5F^2+4F+11

We move all terms to the left:

(F)-(5F^2+4F+11)=0

We get rid of parentheses

-5F^2+F-4F-11=0

We add all the numbers together, and all the variables

-5F^2-3F-11=0

a = -5; b = -3; c = -11;
Δ = b2-4ac
Δ = -32-4·(-5)·(-11)
Δ = -211
Delta is less than zero, so there is no solution for the equation

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